Question

Solve the following equation:​

Answer 1

Answer:

By cross multiplication we get 6y-12=-6y-4

By equating we get 12y=8

y=2/3

Answer 2

$\pink { \underline { \boxed{ \sf{y = \frac{2}{3} }}}}$

Step-by-step explanation:

$\underline{ \underline{\large\green\maltese \large{ \bf \red{Given:-}}}}$

$\boxed{ \sf \frac{2y - 4}{3y + 2} = - \frac{2}{3} }$

$\sf\pink {Cross\: Multiplying, \:i.e., \:multiplying}$$\sf\pink {denominator \:of \:one\: side\: to\:numerator}$$\sf\pink { of\: other \:side\: of \:equation-}$

$\leadsto$$\sf3(2y - 4) = - 2(3y + 2)$

$\sf\green{Applying \:Distributive\: property \:of}$ $\sf\green{ multiplication-}$

$\sf(3 \times 2y) - (3 \times 4) = ( - 2 \times 3) + ( - 2 \times 2)$

$\large↦$$\sf(6y )- (12 )= ( - 6y) + ( - 4)$

$\large↦$$\sf6y - 12 = - 6y - 4$

$\large↦$$\sf6y + 6y = - 4 + 12$

$\large↦$$\sf12y = 8$

$\large↦$$\sf \: y = \frac{ \cancel8}{ \cancel{12} }$

$\large↦$$\sf \: y = \frac{ 2}{3}$