Math, asked by dumpumps, 5 days ago

Solve the following equation

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Answers

Answered by MaiTaeKiQueenHu
1

Answer:

Find common denominator

3

5

3

1

0

=

4

\frac{3x}{5}-\frac{3}{10}=\frac{x}{4}

3

5

+

5

(

3

1

0

)

5

=

4

\frac{3x}{5}+\frac{5\left(-\frac{3}{10}\right)}{5}=\frac{x}{4}

2

Combine fractions with common denominator

3

5

+

5

(

3

1

0

)

5

=

4

\frac{3x}{5}+\frac{5\left(-\frac{3}{10}\right)}{5}=\frac{x}{4}

3

+

5

(

3

1

0

)

5

=

4

\frac{3x+5\left(-\frac{3}{10}\right)}{5}=\frac{x}{4}

3

Multiply the numbers

3

+

5

(

3

1

0

)

5

=

4

\frac{3x+{\color{#c92786}{5}}\left({\color{#c92786}{-\frac{3}{10}}}\right)}{5}=\frac{x}{4}

3

3

2

5

=

4

\frac{3x{\color{#c92786}{-\frac{3}{2}}}}{5}=\frac{x}{4}

4

Multiply all terms by the same value to eliminate fraction denominators

5

Cancel multiplied terms that are in the denominator

2

0

3

3

2

5

=

2

0

4

20 \cdot \frac{3x-\frac{3}{2}}{5}=20 \cdot \frac{x}{4}

4

(

3

3

2

)

=

5

4(3x-\frac{3}{2})=5x

6

Distribute

4

(

3

3

2

)

=

5

{\color{#c92786}{4(3x-\frac{3}{2})}}=5x

1

2

6

=

5

{\color{#c92786}{12x-6}}=5x

7

Add

6

6

to both sides of the equation

1

2

6

=

5

12x-6=5x

1

2

6

+

6

=

5

+

6

12x-6+{\color{#c92786}{6}}=5x+{\color{#c92786}{6}}

8

Simplify

9

Subtract

5

5x

from both sides of the equation

1

2

=

5

+

6

12x=5x+6

1

2

5

=

5

+

6

5

12x{\color{#c92786}{-5x}}=5x+6{\color{#c92786}{-5x}}

10

Simplify

Combine like terms

Combine like terms

7

=

6

7x=6

11

Divide both sides of the equation by the same term

7

=

6

7x=6

7

7

=

6

7

\frac{7x}{{\color{#c92786}{7}}}=\frac{6}{{\color{#c92786}{7}}}

12

Simplify

Cancel terms that are in both the numerator and denominator

=

6

7

x=\frac{6}{7}

Step-by-step explanation:

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Answered by medhanshgoel
0

Answer:

6/7

Step-by-step explanation:

(2(3x)-3)/10=x/4

(6x-3)/10=x/4

4(6x-3)=10x

24x-12=10x

24x-10x=12

14x=12

x=12/14

x=6/7

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