Question

solve the following equation 4z-3/5+1/2=3z+4/4 -2 (-2is not in denominator
)​

Answer 1

Answer:

$\frac{4z - 3}{5} + \frac{1}{2} = \frac{3z + 4}{4} - 2 \\ \frac{2(4z - 3) + 5(1)}{5 \times 2} = \frac{3z + 4 - 2(4)}{4} \\ \frac{8z - 6 + 5}{10} = \frac{3z + 4 - 8}{4} \\ \frac{8z - 1}{10} = \frac{3z - 4}{4} \\ 4(8z - 1) = 10(3z - 4) \\ 32z - 4 = 30z - 40 \\ 32z - 30z = - 40 + 4 \\ 2z = - 36 \\ z = \frac{ \cancel{ - 36} _{ \: \: - 18}}{ \cancel 2 _{ \: \: 1} } \\ \boxed{ \large z = \underline{ \underline{ - 18}}}$