Question

Solve the following equation 5(t+4)+2 (t-6) -3(t+8)=0

Answer 1

Given,

The equation is, 5(t+4)+2 (t-6) -3(t+8)=0

To find,

To calculate the value of the variable (t) of the given equation.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

In this case, we just need to perform step-by-step algebraic operations like multiplication, subtraction or addition, in order to find the value of the given variable.

Value calculation :

5(t+4)+2 (t-6) -3(t+8)=0

5t+20+2t-12-3t-24 = 0

5t+2t-3t = 24-20+12

4t = 16

t = 4

(This value of t will satisfy the initial equation.)

Hence, the value of t is 4

Answer 2

SOLUTION

TO SOLVE

The equation

$\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0}$

EVALUATION

Here the given equation is

$\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0} \: \: ...(1)$

We now solve for t

$\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0}$

$\sf{ \implies \: 5t + 20 + 2t - 12 - 3t - 24= 0}$

$\sf{ \implies \: 4t - 16= 0}$

$\sf{ \implies \: 4t = 16}$

$\sf{ \implies \: t = 4}$

VERIFICATION

We put t = 4 in both sides of Equation (1)

∴ LHS

$\sf{ = 5(t + 4) + 2(t - 6) - 3(t + 8) }$

$\sf{ = 5(4+ 4) + 2(4- 6) - 3(4 + 8) }$

$\sf{ =( 5 \times 8) + (2 \times - 2) - (3 \times 12) }$

$\sf{ =40 - 4 - 36 }$

$= 0$

= RHS

Hence verified

FINAL ANSWER

The required solution is t = 4

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