Math, asked by ahemed8788, 4 months ago

Solve the following equation 5(t-4)+2(t-6)-3(t+8)=0

Answers

Answered by Piyani1716
0

Step-by-step explanation:

SOLUTION

TO SOLVE

The equation

\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0}5(t+4)+2(t−6)−3(t+8)=0

EVALUATION

Here the given equation is

\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0} \: \: ...(1)5(t+4)+2(t−6)−3(t+8)=0...(1)

We now solve for t

\sf{5(t + 4) + 2(t - 6) - 3(t + 8) = 0}5(t+4)+2(t−6)−3(t+8)=0

\sf{ \implies \: 5t + 20 + 2t - 12 - 3t - 24= 0}⟹5t+20+2t−12−3t−24=0

\sf{ \implies \: 4t - 16= 0}⟹4t−16=0

\sf{ \implies \: 4t = 16}⟹4t=16

\sf{ \implies \: t = 4}⟹t=4

VERIFICATION

We put t = 4 in both sides of Equation (1)

∴ LHS

\sf{ = 5(t + 4) + 2(t - 6) - 3(t + 8) }=5(t+4)+2(t−6)−3(t+8)

\sf{ = 5(4+ 4) + 2(4- 6) - 3(4 + 8) }=5(4+4)+2(4−6)−3(4+8)

\sf{ =( 5 \times 8) + (2 \times - 2) - (3 \times 12) }=(5×8)+(2×−2)−(3×12)

\sf{ =40 - 4 - 36 }=40−4−36

= 0=0

= RHS

Hence verified

FINAL ANSWER

The required solution is t = 4

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