solve the following equation. 5(z+3)=4(z+1)
Answers
Answered by
0
please refer the image
thanks
Attachments:
Answered by
0
Step-by-step explanation:
5(z+3) = 4(z+1)
5z+15 = 4z+4
5z-4z = 4-15
z = -11
Putting z = -11 in the given equation,
5[(-11)+3] = 4[(-11)+1]
5[-11+3] = 4[-11+1]
5[-8] = 4[-10]
-40 = -40
Since LHS = RHS
Therefore it is proved that z = -11
Similar questions