Question

solve the following equation

Answer 1

Answer:

(1)  x = $\frac{-68}{11}$ , (2)x = $\frac{15}{8}$ ,(3) x = 1 , (4) x = 1, (5) x = $\frac{-7}{8}$, (6) y = -2,

(7) x = 5 , (8) x = $\frac{11}{3}$, (9) x = 25 and (10) x = 20.

Step-by-step explanation:

Explanation:

• Given, $\frac{x-4}{7} - x = \frac{5-x}{3} +1$

According to the question we need to find the value of x.

⇒$\frac{x-4-7x}{7} =\frac{5-x+3}{3}$

Apply cross multiplication,

⇒3(-6x - 4) = 7(8 - x)

⇒-18x -12 = 56 - 7x

⇒ -11x = 68 ⇒ x = $\frac{-68}{11}$.

• Given,$\frac{5- x}{5 +x} = \frac{2}{5}$

For this equation we need to solve for x.

⇒$\frac{5- x}{5 +x} = \frac{2}{5}$ ⇒ 5(5-x) = 2(5+x)

⇒25 - 5x = 10 + 2x

⇒25 - 10 = 3x + 5x ⇒ 15 = 8x

⇒ x = $\frac{15}{8}$

• Given,(5x -1)(x+3) = (x -5)(5x +1)+ 40

We need to solve this equation for x variable.

⇒$5x^2+ 15x - x - 3 = 5x^2+x -25x-5+40$

⇒14x -3= -24x+35 ⇒ 14x+ 24x = 35 +3

⇒38x = 38 ⇒ x = $\frac{38}{38}$= 1

• Given, $(x+4)^2 -(x-5)^2 = 9$

⇒$x^2 + 16 +8x - (x^2+ 25 - 10x) = 9$

⇒-9 +18x = 9 ⇒ 18x = 18

⇒ x = $\frac{18}{18}$ = 1

• Given,$\frac{8x+7}{5x +9} = 0$

⇒8x + 7 = 0 ⇒ 8x = -7

⇒ x = $\frac{-7}{8}$.

• Given, $\frac{2 - 9y}{17 - 4y} = \frac{4}{5}$

We need to solve the equation for y variable.

⇒$\frac{2 - 9y}{17 - 4y} = \frac{4}{5}$  ⇒5(2 - 9y) = 4(17 - 4y)

⇒10 - 45y = 68 - 16y ⇒10 - 68 = -16 + 45

⇒-58 = 29y  ⇒  y = $\frac{-58}{29}$ = -2.

• Given, 5x -7 = 2x +8

solve for x variable,

⇒5x -2x = 8 + 7

⇒3x = 15 ⇒ x = $\frac{15}{3}$ = 5.

• Given,3(x - 1) = 8

Solve for x variable,

⇒3x -3 = 8 ⇒ 3x = 8 + 3 = 11

⇒ x = $\frac{11}{3}$

• Given, 2(3x + 2) = 154

⇒6x + 4 = 154

⇒6x = 154 - 4 = 150 ⇒ x = $\frac{150}{6}$ = 25.

• Give, 160 - 4x + 6x + 5x = 300

⇒160-4x + 11x = 300

⇒ 160 + 7x = 300 ⇒ 7x = 300 - 160 = 140

⇒x = $\frac{140}{7}$ = 20.

Final answer:

Hence, (1)  x = $\frac{-68}{11}$ , (2)x = $\frac{15}{8}$ ,(3) x = 1 , (4) x = 1, (5) x = $\frac{-7}{8}$, (6) y = -2,

(7) x = 5 , (8) x = $\frac{11}{3}$, (9) x = 25 and (10) x = 20.

#SPJ6