Question

solve the following equation (5x-1)(x+3)=(x-5)(5x+1)+40​

Answer 1

Answer:

(5x-1)(x+3) = (x-5)(5x+1) + 40

5x(x+3) -1(x+3) = x(5x+1) -5(5x+1) + 40

5x^2 + 15x - x-3 = 5x^2 + x-25x^2 -5 + 40

5x^2 + 14x - 3 = 5x^2 - 25x^2 + x - 5 + 40

5x^2 + 14x - 3 = - 20x^2 + x + 35

5x^2 + 20x^2 + 14x - x = 35 + 3

25x^2 + 13x = 38

25x^2 + 13x - 38 = 0

25x^2 + 38x − 25x - 38 = 0

(25x^2 + 38x) + ( −25x − 38 ) = 0

x ( 25x + 38 ) - 1 ( 25x + 38 ) = 0

( x - 1 ) ( 25x + 38 ) = 0

x - 1 = 0 25x + 38 = 0

x = 1 25 x = - 38

x = -38 / 25