Question

solve the following equation 6-3(x-1)=10+(5-2x)

Answer 1

). x/3+x/2=10
take L.H.S part 
x/3+x/2
the L.C.M OF 3 and 2 is 6
now multiplying through out the equation by 6
x/3*6+x/2*6=10*6
2x+3x=60
5x=60
dividing by 5 on both sides
5x/5=60/5
x=2
3). x/2=2x-3
multiplying by 2 on both sides
x/2*2=2*(2x-3)
x=4x-6subtract x on both sides
x-x=4x-6-x
0=3x-6
adding 6 on both sides
0+6=3x-6+6
6=3x
dividing by 3 on both sides
6/3=3x/3
2=x
x=2
plz mark as brain list

Answer 2

6-3x+3=10+5-2x
-x=15-9
x=-6it