Question

SOLVE THE FOLLOWING EQUATION:7(y+3)-2(x+3)=14 AND 4(y-2)+3(x-3)=2

Answer 1

1) 7y+21 - 2x-6 =14
i.e, 7y-2x+15=14
i.e,7y-2x= -1

2) 4y-8 + 3x-9=2
i.e,4y+3x-17=2
i.e, 4y+3x= 19

Multiplying equation 1 by 3 and equation 2 by 2 we get,

4) 21y-6x= -3
5) 8y+6x= 38

Adding equation 4 and 5 we get,
21y-6x= -3
+ 8y+6x= 38
i.e, 29y = 35

Therefore, y= 35/29.
Substituting y=35/29 in equation 4 we get,
21*35/29 -6x= -3
735/29 - 6x= -3

Multiplying throughout by 29,
735 - 174x = -3
Therefore, 174x =735+3
x = 738/174

Therefore, the values of y and x are 35/29 and 738/174 respectively.

Answer 2

ANSHWER

[YOUR ANSHWER]


step(1)

➡ 7(y+3)-2(x+3)=14

➡7y+21-2x-6=14

➡2x-7y=1.....................…….(i) समीकरण
step( 2)

➡4(y-2)+3(x+3)=2

➡4y-8+3x+9=2

➡3x+4y=1....….....…......(ii) समीकरण


समीकरण(i) को 3से तथा समीकरण (ii)को 2 से गुणा करने पर:-

➡➡➡➡➡➡➡6x-21y=3
➡➡➡➡➡➡➡6x+8y=2
➡➡➡➡➡➡➡((-))((-))(((-)))
➡➡➡➡➡➡➡________
➡➡➡➡➡➡➡➡➡-29y=1
➡➡➡➡➡➡➡➡➡y=29


keep value on first step then ➡➡


2x-7(29)=1

2x-203=0

x=203/2

x= 102.5 ANSHWER


i hope it help you☺