Question

SOLVE THE FOLLOWING EQUATION:7(y+3)-2(x+3)=14 AND 4(y-2)+3(x-3)=2

Answer 1

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Answer 2

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▶️ 7(y+3) - 2(x+3) = 14
=> 7y + 21 - 2x - 6 = 14
=> 7y - 2x + 15 = 14
=> 7y - 2x = -1 ------------> (i)

▶️ 4(y-2) + 3(x-3) = 2
=> 4y - 8 + 3x - 9 = 2
=> 4y + 3x -17 = 2
=> 4y + 3x = 2+17
=> 4y + 3x = 19 -------------(ii)

NOW USING SUBSTITUTION METHOD :

From Equation (i)
7y - 2x = -1
7 y = -1+2x
y = -1+2x/7 --------(iii)

PUTTING the value of 'y' in Equation (ii)
4y + 3x = 19
4(-1+2x/7) + 3x = 19
-4 + 8x + 21x = 133
29x = 133 + 4
29x = 137
x = 137/29.....

PUTTING the value of 'x' in Equation (iii)
y = -1+2x / 7
y = -1 +2(137/29)/ 7
y = -1 + (274/29)7
y =( 245/29)/7
y = 35/29....

So, The value of x is 137/29 & y is 35/29✔✔
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