Question

Solve the following equation (a) 10=4+3(t+2) (b) 28=4+3(t+5)

Answer 1

Answer:

10=4+3 (t+2)

10=4+3t+6

10=10+3t

10-10=3t

t=0

b)28=4+3(t+5)

28=4+3t+15

28=19+3t

9=3t

t=3

Answer 2

Answer:

(a)t=-0.571

(b)t=-1

Step-by-step explanation:

(a)10=4+3 (t+2)

10=7 (t+2)

10=7t+14

10-14=7t

7t=-4

t=-4÷7

t=-0.571

(b)28=4+3(t+5)

28=7(t+5)

28=7t+35

28-35=7t

7t=-7

t=-1