Question

Solve the following equation (a)10=4+3(t+2) (b)28=4+(3t+5)​

Answer 1

Answer:

a)10=4+3(t+2)

or,10-4=3t+6

or,6=3t+6

or,3t=6-6

or,3t=0

therefore, t= 0

b))28=4+(3t+5)

or, 28-4=3t+5

or,24=3t+5

or,24-5=3t

or,19=3t

or,3t=19

therefore, t = 19/3

Answer 2

(a) 10 = 4 + 3 ( t + 2 )

10 = 4 + 3t + 6

10 = 4 + 6 + 3t

10 = 10 + 3t

3t = 10 - 10

3t = 0

t = 0/3

t = 0

(b) 28 = 4 + ( 3t + 5 )

28 - 4 = 3t + 5

24 = 3t + 5

24 - 5 = 3t

19 = 3t

19/3 = t