Question

solve the following equation a. 2(y+4)=16 b. -9=3(12+2 c. 3b/2-7=5 d.0=15+5(k-6)​

Answer 1

a.

$2(y + 4) = 16 \\ y + 4 = 16 \div 2 = 8 \\ y = 8 - 4 \\ y = 4$

b.

ur question is incomplete...

c.

$\frac{3b }{2} - 7 = 5 \\ \frac{3b - 14}{2} = 5 \\ 3b - 14 = 5 \times 2 = 10 \\ 3b = 10 + 14 = 24 \\ b = 24 \div 3 \\ b = 8$

d.

$0 = 15 + 5(k - 6) \\ 0 = 15 + 5k - 30 \\ 0 = - 15 + 5k \\ 15 = 5k \\ k = 15 \div 5 \\ k = 3$

Hope this helps you...

Mark as brainliest!!!