Question

SOLVE THE FOLLOWING EQUATION;
a) 4m-7=3/4m-7
b) 3z+11=413z+11
c) 4(x+1)=164(x+1)
d) 2x+14=742x+14=74
e) 4(x+1)=44(x+1)

Answer 1

Step-by-step explanation:

b). 3z + 11 = 413z +11

413z - 3z = 11 - 11

410z = 0

z = 0/410

z = 0

c) 4 ( x + 1 ) = 164 ( x + 1 )

4x + 4 = 164x + 164

4x - 164x = 164 - 4

- 160x = 160

x = -160 / 160

x = -1

d) 2x + 14 = 742x + 14

742x - 2x = 14 - 14

740 x = 0

x = 0 / 740

x = 0

e). 4 ( x + 1 ) = 44 ( x + 1 )

4 x + 4 = 44x + 44

4x - 44x = 44 - 4

- 40x = 40

x = - 40 / 40

x = -1

I didn't get the first question