Question

solve the following equation

a²x²+2ax+1=0,a≠0​

Answer 1

Answer:

a= -1/x

Step-by-step explanation:

a²x²+2ax+1=0

(ax)²+2(ax)(1) +(1)²= 0

by using Identity, x²+2xy+y²=(x+y)²

(ax+1)²=0

ax+1= 0

ax= -1

a= -1/x

Answer 2

Answer:

x=-1/a

Step-by-step explanation:

split the middle term

a²x²+ax+ax+1=0

now

ax(ax+1)+1(1+ax)=0

(ax+1)×(ax+1)=0

x=-1/a

it has only one value of X