solve the following equation algebrically
2x+3y=9 ;3x+4y=5
Answers
Answered by
0
Answer:
8x+12y=36.
9x+12y=15.
- - -
=X= 2 1
Answered by
4
Step-by-step explanation:
given: 2x+3y=9.........(1)
3x+4y= 5..............(2)
equation (1) multiply by 3
so, 3(2x+3y=9)
6x+9y= 27...............(1)
equation (2) multiply by 2
so, 2(3x+4y=5)
6x+8y=10..................(2)
by subtracting equation (2) from (1) i.e., (1)-(2)
we have,
6x+9y-(6x+8y)= 27-10
so, 6x+9y-6x-8y= 17
by eliminating x terms,.....so, by cancelling 6x
we have,
9y-8y=17
so, y=17
by substituting y value in any equation....
we will get x= -21
so, x= -21 , y= 17
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