Question

solve the following equation and check your answer.
3(2x-4)=28-2x​

Answer 1

$3(2x - 4) = 28 - 2x$

$6x - 12 = 28 - 2x$

$6x + 2x = 28 + 12$

$8x = 40$

$x = \frac{40}{8}$

$x = 5$

$Checking \: Equation :$

$3(2x - 4) = 28 - 2x$

$3(2(5) - 4) = 28 - 5(2)$

$3(10 - 4) = 28 - 10$

$3(6) = 18$

$18 = 18$

$L.H.S = R.H.S$

Answer 2

Answer:

The required solution of x$=5$

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question 3(2x-4)=28-2x​

Arrange the equation multiply 3 into (2x-4)=28-2x

$6x-12=28-2x$

We have find the value of "x" in the above question.

Here we will use the transposition method.

Hence, for solving the above equation, we will solve it by separating the like terms at one side to another side,

So, we will shift 12 from LHS to RHS the sign will change from negative to positive,

So, we will shift 2x  from RHS to LHS the sign will change from negative to positive,

As we get,

$6x-12=28-2x\\6x+2x=28+12\\8x=40$

Dividing both side by 8  we get,

$\frac{8x}{8} =\frac{40}{8}\\x=5$

Put the value of x=5 in above equation and check the equation

$3(2x-4)=28-2x\\3(2\times 5-4)=28-2\times5\\3(10-4)=28-10\\3(6)=18\\18=18$

LHS=RHS

Hence the required solution of x$=5$