Question

solve the following equation and check your result 3y+2/3=2y+1​

Answer 1

please show the page of book

Answer 2

The correct answer is $\frac{1}{3}$.

Given: The equation = $\frac{3y+2}{3}=2y+1$.

To Find: The value of y.

Solution:

$3y+\frac{2}{3}=2y+1$

$\frac{9y+2}{3}=2y+1$

9y + 2 = 3(2y + 1)

9y + 2 = 6y + 3

3y = 1

y = $\frac{1}{3}$

Now, to check put the value of y in the equation.

$3y+\frac{2}{3}=2y+1$

$3*(\frac{1}{3}) +\frac{2}{3}=2*(\frac{1}{3}) +1$

$1+\frac{2}{3}=(\frac{2}{3}) +1$

$\frac{5}{3}= \frac{5}{3}$  

Hence proved.

Hence, the value of y is $\frac{1}{3}$.

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