Math, asked by alishahaider658, 5 days ago

solve the following equation and check your solution by substituting it's value in the equation.

1) 6=3(b-4)
2) 3(y+3)+4=28
3) y-2/2=3
4) 3a-7/4 =-4
5) 3(b+4)-7=4b+14

I want the steps by steps explanation please​

Answers

Answered by pavankalyan030400
1

Step-by-step explanation:

6=3(b-4)

b-4=6/3

b-4=2

b=6

substituting b values

6=3(6-4)

6=3(2)

6=6

3(y+3)+4=28

3y+9+4=28

3y+13=28

3y=28-13

3y=15

y=15/3=5

check

3(5+3)+4=28

3(8)+4=28

24+4=28

28=28

y-2/2=3

y-1=3

y=4

check

4-1=3

3=3

3(b+4)-7=4b+14

3b+12-7=4b+14

3b+5=4b+14

5-14=4b-3b

b=-9

check

3(-9+4)-7=4(-9)+14

3(-5)-7=-36+14

-15-7=-22

-22=-22

Answered by drish79
1
Step wise explanation the last question answer will be B=-9 you can put nd check yourself
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