Solve the following equation and verify your answer....
Answers
Answer:
(4x + 1)/(3x - 1) = 2
4x + 1 = 2(3x - 1)
4x + 1 = 6x - 2
1 + 2 = 6x - 4x
3 = 2x
x = 3/2...
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Answer:
The value of x are 1 and 3.
Step-by-step explanation:
we need to solve the expression for the value of x
\frac{3}{x+1}-\frac{1}{2}=\frac{2}{3x-1}
x+1
3
−
2
1
=
3x−1
2
Take L.C.M in above expression
\frac{6-(x+1)}{2(x+1)}=\frac{2}{3x-1}
2(x+1)
6−(x+1)
=
3x−1
2
\frac{6-x-1}{2(x+1)}=\frac{2}{3x-1}
2(x+1)
6−x−1
=
3x−1
2
\frac{5-x}{2x+2}=\frac{2}{3x-1}
2x+2
5−x
=
3x−1
2
Multiply both the sides by (2x+2)(3x-1)(2x+2)(3x−1)
(5-x)(3x-1)=2(2x+2)(5−x)(3x−1)=2(2x+2)
15x-5-3x^{2}+x=4x+415x−5−3x
2
+x=4x+4
subtract both the sides by 4x+4 in above expression,
15x-5-3x^{2}+x-4x-4=015x−5−3x
2
+x−4x−4=0
Combine like terms together,
-3x^{2}+x+15x-4x-4-5=0−3x
2
+x+15x−4x−4−5=0
-3x^{2}+12x-9=0−3x
2
+12x−9=0
divide both the sides by -3 in above expression
x^{2}-4x+3=0x
2
−4x+3=0
x^{2}-x-3x+3=0x
2
−x−3x+3=0
x(x-1)-3(x-1)=0x(x−1)−3(x−1)=0
(x-1)(x-3)=0(x−1)(x−3)=0
if x-1 =0 ⇒ x=1
if x-3 =0 ⇒ x=3