Math, asked by pdagrawal707, 5 months ago

Solve the following equation by completing the
square method:
x2 + 4x + 1 = 0
Answer
O (V + 2) and (- v 1 + 2)
O (V15-2) and (- v * + 2)
O (v + 2) and (- v5 - 2)
O (v + + 2) and (v 15 - 2)​

Answers

Answered by vk0435362
0

Answer:

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Step-by-step explanation:

(ax^2)+bx+c=0

x= [-b+√{(b^2)-4ac}]/2a or [-b-√{(b^2)-4ac}]/2a

(x^2)+4x+1=0

x= [-4(+/-)√{(4^2)-4(1)(1)}]/2(4)

x={-4(+/-)4√3}/8

x= {-1(+/-)√3}/2

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