Math, asked by mahim989, 8 months ago

Solve the following equation by completing the square2x²+21x-50=0​

Answers

Answered by debimukh
1

Answer:

2

Step-by-step explanation:

2x² + 21x - 50 = 0

or, 2x² + 25x - 4x - 50 = 0

or, x( 2x + 25) - 2( 2x + 25) = 0

or, ( x - 2 )( 2x + 25 ) = 0

or, x - 2 = 0/(2x + 25 )

or, x - 2 = 0

or, x = 2

Answer = 2.

Answered by balisaini0
1

Answer:

There is your answer

Step-by-step explanation:

2x^2 + 21x - 50 = 0

2x^2 + 25x - 4x - 50 = 0

x(2x + 25) -2(2x + 25) = 0

(x - 2) (2x + 25) = 0

If you want value of x then,

x - 2 = 0 | 2x + 25 = 0

x = 2 | 2x = -25

| x = -25/2

x has two values.

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