Question

solve the following equation by cramer's method 6x-3y=-8;3x+5y-8=0
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Answer 1

Given :   6x-3y=-8

3x+5y-8=0  

To Find  : solve using Cramer's method

Solution:

6x-3y=-8  

3x+5y-8=0  

=> 3x + 5y = 8

6x - 3y = -8  

3x + 5y = 8

$\left[\begin{array}{ccc}6&-3\\3&5\end{array}\right] = 6\times5-( 3)\times(-3)=39$

$\left[\begin{array}{ccc}-8&-3\\8&5\end{array}\right] = -8\times5-( 8)\times(-3)=-16$

x = -16/39

$\left[\begin{array}{ccc}6&-8\\3&8\end{array}\right] = 6\times8-( 3)\times(-8)=72$

y = 72/39  = 24/13

y = 24/13

or

6x-3y=-8  

3x + 5y = 8  => 6x + 10y  = 16

=> 13y = 24

=> y = 24/13

3x + 5y = 8

=> 3x + 5(24/13) = 8

=> x = -16/39

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