solve the following equation by elimination and cross multiplication method. 3x+y=7, 4x+5y=14..pls do stp by stp
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3x + y = 7 , 4x + 5y = 14
3x + y = 5
x= 1÷3 ( -y+7)
x= -1÷3y +7÷3
4 [ -1÷3 y + 7÷3 ] +5y = 14
-4÷3y + 28 ÷ 3 + 5y = 14
11÷ 3 y = 14 ÷ 3
y = 14 ÷ 11
x = -1÷3 × (14÷ 11)+7÷3
x = 21 ÷11
x = 14 ÷ 11
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