Question

solve the following equation by elimination method ​
I will mark as brainliest

Answer 1

Let 1/(3x+2y) be a

and

1/(3x-2y) be b

So equations become

2a + 3b = 17/5

10a + 15b = 17 ________(1)

AND

5a+b = 2

Multiplying it by 2

10a + 2b = 4 ________(2)

Solving (1) & (2)

10a + 15b = 17

10a + 2b = 4
- - - _________________
13b = 13

b = 1

Putting value of b in 5a+b=2

a = 1/5

1/(3x+2y) = a

1/(3x+2y) = 1/5

3x+2y = 5 _______(3)

And

1/(3x-2y) = b

1/(3x-2y) = 1

3x-2y = 1 ________ (4)

Solving 3 and 4

3x + 2y = 5

3x - 2y = 1
- + - ______________
4y = 4

y = 1

Putting value of y in (4)

x= 1

Therefore x = 1 and y= 1 are required solutions