Question

solve the following equation by elimination method:x+y=5,2x-3y=4​

Answer 1

$Given \: pair \:of \: equations :$

$x + y = 5 \: ---(1)$

$and \: 2x - 3y = 4 \: ---(2)$

/* Multiplying equation (1) by 3 and add equation (2) , we get */

$\implies 3x + 3y + 2x - 3y = 15 + 4$

$\implies 5x = 19$

$\implies x = \frac{19}{5}$

/* Put value of x in equation (1) , we get */

$\frac{19}{5} + y = 5$

$\implies y = 5 - \frac{19}{5}$

$\implies y = \frac{25-19}{5}$

$\implies y = \frac{6}{5}$

Therefore.,

$\green { x = \frac{19}{5} \:Or \: y = \frac{6}{5} }$

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