Solve the following equation by equating coefficient method
5x+7y=4
3x+2y=16
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Step-by-step explanation:Given simultaneous equations are ,
5x + 7y = 17
multiply both sides with 2 , we get
10x + 14y = 34 ---( 1 )
3x - 2y = 4
multiply both sides with 7 , we get
21x - 14y = 28 ---( 2 )
Add ( 1 ) & ( 2 ) , we get
31x = 62
=> x = 62/31
=> x = 2
substitute x = 2 in equation ( 1 ) ,
10 × 2 + 14y = 34
=> 20 + 14y = 34
=> 14y = 34 - 20
=> 14y = 14
=> y = 14/14
y = 1
Therefore ,
x = 2 , y = 1
••••
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