Question

Solve the following equation by formula method- d) 3y² = y +1​

Answer 1

Answer:

$3{y}^{2} = y + 1 \\ 3 {y}^{2} - y - 1 = 0 \: \\ here \: a = 3 \: and \: \: b = - 1 \: and \: \: c = - 1 \: \\ we \: know \: that \: \\ x = \frac{ - (b) \frac{ + }{ \: } \sqrt{ {b}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 1) \frac{ + }{ \: } \sqrt{ {( - 1)}^{2} - 4( - 1)(3)} }{2(3)} \\ = \frac{1 \frac{ + }{ \: } \sqrt{1 + 12} }{6} \\ = \frac{1 \frac{ + }{ \: } \sqrt{13} }{6} \\ y = \frac{1 \frac{ + }{ \: } \sqrt{13} }{6}$

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