Math, asked by Anonymous, 3 days ago

solve the following equation by quadratic formula
5 {x}^{2}   - 8x - 4 = 0
can anyone solve this question​

Answers

Answered by Sanju1534
3

Answer:

 {5x}^{2}  - 8x - 4 = 0

 {5x}^{2}  - (10 - 2)x - 4 = 0

 {5x}^{2}  - 10x + 2x - 4 = 0

5x(x - 2) + 2(x - 2) = 0

(5x + 2)(x - 2) = 0

(5x + 2) = 0 \: and \: (x - 2) = 0

x = -2/5 and x = 2

Ans. -2/5, 2

Hope it helps.

Answered by Mysteryboy01
0

 = 5 {x}^{2}  - 8x - 4

 = 5 {x}^{2}  - (10 - 2)x - 4

 = 5 {x}^{2}  - 10x + 2x - 4

 = 5x(x - 2) + 2(x - 2)

 =( 5x + 2)(x - 2)

5x + 2 = 0

5x =  - 2

x =  \frac{ - 2}{5}

x - 2 = 0

x = 2

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