solve the following equation by the co-effcients 1) 7a-4b=5; 3a+2b=7
Answers
Answer:
Identify the monomials, binomials, trinomials and quadrinomials from the following expressions:
(i) a2
(ii) a2 − b2
(iii) x3 + y3 + z3
(iv) x3 + y3 + z3 + 3xyz
(v) 7 + 5
(vi) a b c + 1
(vii) 3x – 2 + 5
(viii) 2x – 3y + 4
(ix) x y + y z + z x
(x) ax3 + bx2 + cx + d
Solution:
(i) Given a2
a2 is a monomial expression because it contains only one term
(ii) Given a2 − b2
a2 − b2 is a binomial expression because it contains two terms
(iii) Given x3 + y3 + z3
x3 + y3 + z3 is a trinomial because it contains three terms
(iv) Given x3 + y3 + z3 + 3xyz
x3 + y3 + z3 + 3xyz is a quadrinomial expression because it contains four terms
(v) Given 7 + 5
7 + 5 is a monomial expression because it contains only one term
(vi) Given a b c + 1
a b c + 1 is a binomial expression because it contains two terms
(vii) Given 3x – 2 + 5
3x – 2 + 5 is a binomial expression because it contains two terms
(viii) Given 2x – 3y + 4
2x – 3y + 4 is a trinomial because it contains three terms
(ix) Given x y + y z + z x
x y + y z + z x is a trinomial because it contains three terms
(x) Given ax3 + bx2 + cx + d
ax3 + bx2 + cx + d is a quadrinomial expression because it contains four terms
Step-by-step explanation:
7a-3a=5,4b+2b=7
4a=5,6b=7
a=5-4=1
b=7-6=1
therefore,a=1 and b=1