solve the following equation by the method of completing the square: 2x^2 + 4x - 16 = 0
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Question
solve the following equation by the method of completing the square: 2x^2 + 4x - 16 = 0
Solution
Quadratic Equation is ,
==> 2x² + 4x - 16 = 0
Factories by, Complete Square method
Steps 1.
First take " constant part in R.H.S.
==> 2x² + 4x = 16
Steps 2.
Divided by " 2 " both sides
==> 1/2 * ( 2x² + 4x ) = 16/2
==> 2x²/2 + 4x/2 = 8
==> x² + 2x = 8
Steps 3.
Add " 1 " both Side
==> x² + 2x + 1 = 8 + 1
==> x² + 2 * x * 1 + 1² = 9
We know
★ (a+b)² = a² + b² + 2ab
So,
==> (x + 1)² = 9
==> (x + 1) = ± √9
==> x + 1 = ± 3
Take first (-)ve Sign
==> x + 1 = -3
==> x = -3 - 1
==> x = -4
Take Second (+) ve sign
==> x + 1 = 3
==> x = 3 - 1
==> x = 2
Hence
- Value of given equation will be = 2 & -4
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