Question

solve the following equation by the substitution x-y = 0.9 ; 11/ 2 ( X + y ) = 1

Answer 1

Holla ^_^

x-y=0.9

x=0.9+y

11/2(x+y)=1

11/2(0.9+y+y)=1

11/2(0.9+2y)=1

0.9+2y=2/11

2y=2/11-0.9

2y=2/11-9/10

2y=-79/110

y=-79/110*2

y= -79/220

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Answer 2

$\underline{\bold{Answer:-}}$


$\\ x - y = 0.9 - - - (1)$

$\frac{11}{2} (x + y) = 1 \\ \\ = > \frac{11x}{2} + \frac{11y}{2} = 1 \\ \\ = > \frac{11x + 11y}{2} = 1 \\ \\ = > 11x + 11y = 2 - - - (2)$

From eq'n ( 1 )

$x - y = 0.9 \\ \\ = > x = 0.9 + y - - - (3)$

Substitute eq'n ( 3 ) in eq'n ( 2 )

$11x + 11y = 2 \\ \\ = > 11(0.9 + y) + 11y = 2 \\ \\ = > 9.9 + 11y + 11y = 2 \\ \\ = > 22y + 9.9 = 2 \\ \\ = > 22y = 2 - 9.9 \\ \\ = > 22y = - 7.9 \\ \\ = > y = \frac{ - 7.9}{22}$

From eq'n ( 3 )

x = 0.9 + y

=> x = 0.9 + ( - 7.9 / 22 )

=> x = 0.9 - 7.9 / 22

=> x = 19.8 - 7.9 / 22

=> x = 11.9 / 22

Hence, the value of x = 11.9 / 22 and y = - 7.9 / 22.



$\textbf{Hope it helps!}$