Question

solve the following equation by transposition method and check your result (d) 5(6x - 1) =3(8 + x)-2 .​

Answer 1

Step-by-step explanation:

5(6x - 1) = 3(8 + x) - 2

5 × 6x - 5 × 1 = 3 × 8 + 3x - 2

30x - 5 = 24 -2 + 3x

30x - 5 = 22 + 3x

30x - 3x = 22 + 5

27x = 27

x = 27/27

x = 1

Answer 2

Given -

• 5(6x - 1) = 3(8 + x ) -2

To -

• Solving the equation by transposition method.

Solution -

Let LHS be 5(6x - 1) and RHS be 3(8 + x) -2

On solving the equation -

→ 30x - 5 = 24 + 3x - 2

→ 30x - 3x = 24 - 2 + 5

→ 27x = 27

→ x = 27/27

$\implies$ x = 1

$\therefore$ Value of x is 1

Checking the Answer -

By placing 1 in place of x -

5(6(1) - 1) = 3(8 + (1)) -2

→ 5(6 - 1) = 24 + 3 - 2

→ 30 - 5 = 27 - 2

→ 25 = 25

$\therefore$ LHS = RHS

Procedure -

• This question is from linear equation.

• In the above given equation we arr give constants + variables in a bracket. And one constant (number) is given before those brackets.

• In maths, we have to always multiply that constant with that variable/ constant. Means whenever any number will be give outside the bracket and any constant or variable inside the bracket we will always multiply it.

• After that we will transpos the RHS constants (which have x) with LHS constant and LHS constants to the RHS constant (which Don't have x).

• And in the end both will get cancelled then the value of x will be 1. For checking the Answer will put 1 in place of x and then will

equate it again, as we have done in the solution part.

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