Question

solve the following equation by trial and error method 1 x+3=5 2 5y=15​

Answer 1

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

⋆ The question says that we have to solve the following linear equations by using trial and error method. Let's solve this question!

$\rule{95}{5}$

Question: x+3 = 5

Explanation: To solve the questions related to linear equation in a variable by trial and error method. We have to put numbers from 0 to so on till the answer does not came. If we put 1 at the place of variable and answer doesn't came then we have to put 2 then if answer came then it's nice but if not then we have to try. Let's see how to solve!

Required solution:

Putting 1 at the place of x

⟹ x+3 = 5

⟹ 1+3 = 5

⟹ 4 = 5

⟹ 4 ≠ 5

⟹ LHS ≠ RHS

⠀⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━

Now putting 2 at the place of x

⟹ x+3 = 5

⟹ 2+3 = 5

⟹ 5 = 5

⟹ LHS = RHS

• x+3=5
• 2+3=5

Henceforth, the question is solved, 2 is the requied solution for the part first.

$\rule{95}{5}$

Question: 5y=15

Explanation: To solve the questions related to linear equation in a variable by trial and error method. We have to put numbers from 0 to so on till the answer does not came. If we put 1 at the place of variable and answer doesn't came then we have to put 2 then if answer came then it's nice but if not then we have to try. Let's see how to solve!

Required solution:

Putting 1 at the place of y

⟹ 5y = 15

⟹ 5(1) = 15

⟹ 5 = 15

⟹ 5 ≠ 15

⟹ LHS ≠ RHS

⠀⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━

Putting 2 at the place of y

⟹ 5y = 15

⟹ 5(2) = 15

⟹ 10 = 15

⟹ 10 ≠ 15

⟹ LHS ≠ RHS

⠀⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━

Putting 3 at the place of y

⟹ 5y = 15

⟹ 5(3) = 15

⟹ 15 = 15

⟹ LHS = RHS

• 5y = 15
• 5(3) = 15

Henceforth, the question is solved, 3 is the requied solution for the part second