Question

solve the following equation by trial and error method i) 5p​ +2 =17

Answer 1

Answer:

5p + 2 = 17

5p = 17-2

5p = 15

p = 15÷ 5

p = 3

Step-by-step explanation:

we got the equation 5p + 2 = 17

we know that we have one variable. 2 is getting added. when transferring it to the next side it will be subtracted.

we will get 5p = 17- 2. after subtracting it will be 15. now only 5p =15 is left . 5 is multiplied with p when transferred to the next side it will be dived and we will get the value 3.

I HOPE IT HELPS.

Answer 2

LHS = 5p + 2

By substituting the value of p = 0

Then,

LHS = 5p + 2

= (5 × 0) + 2

= 0 + 2

= 2

Now let's compare LHS and RHS

2 ≠ 17

LHS ≠ RHS

Hence, the value of p = 0 is not a solution to the given equation.

Let, p = 1

LHS = 5p + 2

= (5 × 1) + 2

= 5 + 2

= 7

Now let's compare LHS and RHS

7 ≠ 17

LHS ≠ RHS

Hence, the value of p = 1 is not a solution to the given equation.

Let, p = 2

LHS = 5p + 2

= (5 × 2) + 2

= 10 + 2

= 12

Now let's compare LHS and RHS

12 ≠ 17

LHS ≠ RHS

Hence, the value of p = 2 is not a solution to the given equation.

Let, p = 3

LHS = 5p + 2

= (5 × 3) + 2

= 15 + 2

= 17

By comparing LHS and RHS

17 = 17

LHS = RHS

Hence, the value of p = 3 is a solution to the given equation.