Question

solve the following equation by using formula (2x+3)(3x-2)+2=0​

Answer 1

$\red{soution} \\ = > (2x + 3)(3x- 2) + 2 = 0 \\ \\ = > 6x^{2} - 4x + 9x - 6 + 2 = 0\\ \\ = > 6 {x}^{2} + 5x - 4 = 0 \\ \\ = > 6 {x}^{2} - 3x + 8x - 4 = 0 \\ \\ = > 3x(2x - 1) + 4( 2x - 1) = 0 \\ \\ = > (2x - 1)(3x + 4) = 0 \\ \\ = > (2x - 1) = 0 \: \: or \: \: (3x + 4) = 0 \\ \\ = > 2x = 1 \: \: or \: \: 3x = - 4 \\ \\ => x = \frac{1}{2} \: \: or \: \: x = \frac {- 4}{3}$

$\fcolorbox{blue}{aqua} {i \: hope \:it \: helps \: you.}$