Question

solve the following equation by using quadratic equation for x: x²-5x-10=0​

Answer 1

Given:

• A quadratic equation is given to us.
• The equⁿ is x²-5x-10 = 0.

To Find:

• The values of x .

Answer:

The given quadratic equation to us is x²-5x-10=0.

Here the discriminant b²-4ac = 5²-4×1×-10 = 25+40= 65. And 65 is not a square of any number , hence rhe roots will Irrational conjugates.

We would find the roots using Standard formula , which is -b±√b²-4ac/2a .

=> x = -(-5) ± √(-5)² -4×1×-10/2×1

=> x = 5 ± √25+40/2

=> x = 5 ± √65/2

=> x = 5/2 ± √65/2.

=> x = 5+√65/2 , 5-√65/2

Answer 2

Step-by-step explanation:

• x^2 + 5x - 10 = 0
• x = -b (+/-) √b^2 - 4ac........(1)
• a = 1

b = 5

c = -10

• substituting the values of a,b,c in (1)
• x = -5 (+/-) √(-5^2) - 4×1× -10
• x = -5 (+/-) √25 + 40
• x = -5 (+/-) √65

1. x = -5 + √65

x = -5 + 8.062

x = 3.062

2. x = -5 - √65

x = -5 - 8.062

x = -13.062

values of x = 3.062 and -13.062

HOPE THIS HELPS U