Question

Solve the following equation
c)3(n-5)=-21
d)-4(2+x)=8
e)4(2-x)=8

Answer 1

Step-by-step explanation:

first ill show u the appropriate steps

e) Given 4 (2-x)=8;

Step 1: Multiply 4 with (2-x)

Steps 2: After multiplying we get the value as

Step 3:8-4x=8;

Step 4: We need to find the value of x so simplify the equation accordingly.

Step 5: So move 8 to RHS, while moving 8 will be changed as -8

Step 6: -4x=8-8;

Step 7:-4x=8-8;

Step 8: From the step 7, 8 and -8 will become zero.

Step 9:-4x=0.

Step 10: As we need to find the value of x, so move the -4 to RHS, which can be written as

Step 11: -x=0/4,

Step 12:0/4 which is zero

Step 13=-4x=0.

Step 14: So the value of X is Zero.

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now, with this try to understand c and d

c) 3(n-5)=21

3n-15=21

3n= 36

n= 12

d)-4(2+x)=8

-8+x=8

X=16

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