Question

solve the
following equation
equation x + 5 upon 2 = 1 - x​

Answer 1

Given:

The equation -

$\underline{\boxed{ \bf \dashrightarrow \dfrac{x+5}{2} = 1-x}}$

What To Find:

We have to

• First, solve the given equation.
• Second, find the value of x.

How To Find:

To find it we have to

• First, simplify both sides one by one.
• Next, take the constant to one side.
• Then, take the variable to another side.
• Then, solve the equation.
• Finally, you will get an answer.

Solution:

$\rm \longmapsto \dfrac{x+5}{2} = 1-x$

Use cross multiplication method,

$\rm \longmapsto x+5 = 2(1-x)$

Remove the brackets.

$\rm \longmapsto x+5 = 2 - 2x$

Take x to RHS,

$\rm \longmapsto 5 = 2 - 2x - x$

Take 2 to LHS,

$\rm \longmapsto 5 - 2 = - 2x - x$

Subtract 2 from 5,

$\rm \longmapsto 3 = - 2x - x$

$\rm \longmapsto 3 = - 3x$

Take -3 to LHS,

$\rm \longmapsto -\dfrac{3}{3} = x$

Divide -3 by 3,

$\rm \longmapsto -1 = x$

Verification:

$\rm \longmapsto \dfrac{x+5}{2} = 1-x$

Substitute the value of x,

$\rm \longmapsto \dfrac{-1+5}{2} = 1-(-1)$

Add the numerator in LHS,

$\rm \longmapsto \dfrac{4}{2} = 1-(-1)$

Divide 4 by 2 in LHS,

$\rm \longmapsto 2 = 1-(-1)$

Remove the brackets in RHS,

$\rm \longmapsto 2 = 1 + 1$

Add 1 + 1 in RHS,

$\rm \longmapsto 2 = 2$

∵ LHS = RHS

∴ Hence, the equation is verified.

Final Answer:

∴ Hence, the value of x in the equation is - 1.