Question

Solve the following equation for x & y : 3x + 6y = 5 and 4x - 5y = 8

Answer 1

Answer:

x = 73/39

y= -4/39

Step-by-step explanation:

by substituting the value of X in any equation first or second . we get the value of y.

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Answer 2

x = $\frac{73}{39}$

y = - $\frac{4}{39}$

Step-by-step explanation:

Given,

3x + 6y = 5

4x - 5y = 8

Let, 3x + 6y = 5 be equation I and,  4x - 5y = 8 be equation II

Finding the value of x from equation I:

3x + 6y = 5

3x = 5 - 6y

x = $\frac{5 - 6y}{3}$

Substituting the value of x in equation II:

4x - 5y = 8

4 $(\frac{5 - 6y}{3})$ - 5y = 8

$(\frac{4 * 5 - 4 * 6y}{3})$ - 5y = 8

$(\frac{20 - 24y}{3})$ - 5y = 8

$(\frac{20 - 24y - 3 * 5y}{3})$ = 8

$(\frac{20 - 24y - 15y}{3})$ = 8

20 - 39y = 8 × 3

20 - 39y = 24

-39y = 24 - 20

-39y = 4

y = - $\frac{4}{39}$

Substituting the value of y in equation I:

3x + 6y = 5

3x + (6 × - $\frac{4}{39}$) = 5

3x -  $\frac{24}{39}$ = 5

$\frac{3x * 39 - 24}{39}$ = 5

3x ×  39 - 24 = 5 ×  39

117x - 24 = 195

117x = 195 + 24

117x = 219

x = $\frac{219}{117}$

Dividing both numerator and denominator by 3:

x = $\frac{73}{39}$

x = $\frac{73}{39}$

y = - $\frac{4}{39}$

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