Math, asked by rohanbalaggan, 6 months ago

Solve the following equation for x and give your answer: Correct to two decimal

places: 3x^2 + 5x -9 = 0.​

Answers

Answered by padigarbhavani
23

Answer:

3x² + 5x - 9 = 0

a = 3, b = 5, c = -9

x = (-b ± √b² - 4ac) / 2a

x = {-5 ± √5² - 4(3)(-9)} / 6

x = {-5 ± √25 + 108} / 6

x = {-5 ± √133} / 6

x ≈ 1.09 or x ≈ -2.76.

Step-by-step explanation:

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Answered by ajajit9217
3

Answer:

The value of x is 1.09 or - 2.76

Step-by-step explanation:

Given equation is 3x² + 5x - 9 = 0

We know that x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

here,  a = 3

b = 5

c = -9

Substituting, the values, we get,

x = \frac{-(5) \pm \sqrt{5^2 -4*3*(-9)}}{2*3}

=>  x = \frac{-5 \pm \sqrt{25 +108}}{6}

=>  x = \frac{-5 \pm \sqrt{133}}{6}

=>  x = \frac{-5 \pm 11.53 }{6}

=> x = \frac{-5 + 11.53 }{6} or x = \frac{-5 - 11.53 }{6}

=> x = \frac{6.53 }{6} or x = \frac{- 16.53 }{6}

=> x = 1.08833 or x = -2.755

=> x = 1.09 or x = - 2.76

Therefore, the  value of x is 1.09 or - 2.76

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