Question

Solve the following equation for x

${4}^{2x} = \frac{1}{32}$
​

Answer 1

Step-by-step explanation:

Given :

${4}^{2x} = \frac{1}{32}$

Find :

The value of x.

Solution :

$= > ( {2}^{2} )^{2x} = (\frac{1}{5} ) ^{5}$

$= > {2}^{4x} = {2}^{ - 5}$

$= > 4x = - 5$

$= > x = \frac{ - 5}{4} \: \: or \: \: - \frac{5}{4} .$

Hence :

The value of x is -5/4.

Brainly Question number :

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Answer 2

$✯\tt{\tt\red{Question \:}} : -$

TO FIND IN EQUATION IS = x

✯$\sf ANSWER$✵

$⟹ {2}^{4x} = {2}^{ - 5}$

★$4x = - 5=>4x=−5$★

$\sf ➪ x = \frac{ - 5}{4} \: \: or \: \: - \frac{5}{4} .$

✵Therefore✵

★The value of x is -5/4.★