Question

solve the following equation in cross multiplication method: x+y=5 , 3x+2y=8
plz answer....
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Answer 1

2x+y−5=0

3x+2y-8=03x+2y−8=0

$\textbf{By cross multiplication rule,}$

$</p><p>\displaystyle\frac{x}{-8+10}=\frac{y}{-15+16}=\frac{1}{4-3}$

$\displaystyle\implies\frac{x}{2}=\frac{y}{1}=\frac{1}{1}$

$\implies\;x=2\;\text{and}\;y=1 \\ </p><p>\therefore\textbf{The solution is x=2 and y=1 }$

Answer 2

2x+y−5=0

3x+2y−8=0

Using cross multiplication method, we get

b

1

c

2

−b

2

c

1

x

=

c

1

a

2

−c

2

a

1

y

=

a

1

b

2

−a

2

b

1

1

2

x

=

+1

y

=

1

1

So, x=2 and y=+1