Question

Solve the following equation in substitution method
3x-2y=0
4x+3y=0

Answer 1

3x-2y=0

if x=1,

=>3(1)-2y=0

=>3-2y=0

=>-2y=-3

=>y=3/2

=>(x,y)=(1,3/2)

if x=0,

=>3(0)-2y=0

=>-2y=0

=>y=0

=>(x,y)=(0,0)

4x+3y=0

if x=0,

=>4(0)+3y=0

=>3y=0

=>y=0

=>(x,y)=(0,0)

if x=1

=>4(1)+3y=0

=>4+3y=0

=>3y=-4

=>y=-4/3

=>(x,y)=(1,-4/3)

HOPE U CAN UNDERSTAND

Answer 2

hai friend,
here is your answer

the equations are 3x-2y=0…[1]
4x+3y=0………[2]

from [1] 3x=2y
x=2y/3…[3]


substituting value of x in [2]

4(2Y)/3+3Y=0
(8/3+3)Y=0
Y(17)/3=0
Y=0

SUBSTITUTING Y IN EQUATION [3]

X=2/3*0
X=0
THERE FORE

(X,Y)=(0,0)

HOPE HELPED