Question

Solve the following equation m-5/2-m-3/5=1/2

Answer 1

Step-by-step explanation:

Answer

The above question can be written as,=3×[(2m+5)/3]=3×(3m−10)...[Multiplying both side by 3]

⇒(2m+5)=9m−30

Transposing 2m to RHS and it becomes −2m and −30 to LHS it becomes 30

⇒30+5=9m−2m

⇒35=7m

Multiplying both side by (1/7),

⇒7m×(1/7)=35×(1/7)

⇒m=(35/7)

⇒m=5

By substituting 5 in the place of m in given equation, we get

LHS,

=2m+5

=2×(5)+5

=10+5

=15

RHS,

=9m−30

=9×(5)−30

=45−30

=15

By comparing LHS and RHS

⇒15=15

∴LHS=RHS

Hence, the result

Answer 2

Answer:

Given (x−5)/2−(x−3)/5=1/2

Now by taking L.C.M for 5 and 2 is 10

⇒

10

(5(x−5)−2(x−3))

=1/2

By transposing the above equation we can write as

⇒(5x−25−2x+6)=10/2

⇒3x−19=5

Again by transposing

⇒3x=19+5=24

⇒x=24/3=8