Question

solve the following equation of the Simultaneous linear equations: x/3 + y/4 =4 ; 5x/6 - y/8=4​

Answer 1

$\huge \rm {Answer:-}$

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$\bf\orange{Given:-}$

$\tt {\fbox {Equation\: 1,}}$

$\large \dashrightarrow \tt{\frac{x}{3}+\frac{y}{4}=4}$

★"By Taking LCM",

$\large \dashrightarrow \tt{\frac{4x+3y}{12}=4}$

$\dashrightarrow \tt{4x+3y=4\times12}$

$\dashrightarrow \tt{4x+3y=48}$

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$\tt {\fbox {Equation\: 2,}}$

$\large \dashrightarrow \tt{\frac{5x}{6}-\frac{y}{8}=4}$

★"By Taking LCM",

$\large \dashrightarrow \tt{\frac{5x(4)-y(3)}{24}=4}$

$\large \dashrightarrow \tt{\frac{20x-3y}{24}=4}$

$\dashrightarrow \tt{20x-3y=4\times24}$

$\dashrightarrow \tt{20x-3y=96}$

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★"As the co-efficients of 'y' are equal in the both equations but with contrasting signs,we can sum up the two equations".

$\bf\blue{On\: Adding:-}$

$\dashrightarrow \tt {4x+3y+20x-3y=48+96}$

★"y" gets cancelled,so we get:-

$\dashrightarrow \tt {4x+20x=144}$

$\dashrightarrow \tt {24x=144}$

$\dashrightarrow \tt {x=\frac{144}{24}}$

$\large \tt {\fbox{x=6}}$

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★"Substituting the value of 'x' in either of the equations gives the value of 'y' "

$\bf\pink{Substituting\: X=6\: in\: eq- 1,}$

$\dashrightarrow \tt{4(6)+3y=48}$

$\dashrightarrow \tt{24+3y=48}$

$\dashrightarrow \tt{3y=48-24}$

$\dashrightarrow \tt{3y=24}$

$\large \dashrightarrow \tt{y=\frac{24}{3}}$

$\large \tt {\fbox{y=8}}$

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$\bf\purple{Thereupon,}$

$\large \tt {\fbox{x=6\: and\:y=8}}$

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Answer 2

Answer:

hey mate :-

Step-by-step explanation:

On solving the both equations,we get

X value = 6 and y value =8

thank you,hope it helps you !