Question

Solve the following equation please
3 (2p-1) = 5-(3 p - 2 )​

Answer 1

Required Answer:-

Given:

• 3(2p - 1) = 5 - (3p - 2)

To Find:

• The value of p.

Solution:

Given,

➡ 3(2p - 1) = 5 - (3p - 2)

➡ 6p - 3 = 5 - 3p + 2

➡ 6p + 3p = 7 + 3

➡ 9p = 10

➡ p = 10/9

Hence, the value of p satisfying the given equation is 10/9

Answer:

• p = 10/9

Answer 2

Answer:

Value of p = $\sf{\dfrac{10}{9}}$

Step-by-step explanation:

Given :

3(2p-1)=5-(3p-2)

To find :

The value of p

Solution :

>> 3(2p-1)=5-(3p-2)

Use the cross multiplication

>> 6p-3=5-3p+2

>> 6p+3p=5+2+3

Add the (+) integer and then

>> 9p=10

>> p=10/9

So , the value of p is 10/9 .

Verification :

To verify the equation find the value of LHS and RHS . If the value will be same then the answer wi be verified.

$:\implies\sf{3(2\times\dfrac{10}{9}-1)=5-(\cancel{3}\times\dfrac{10}{\cancel{9}}-2)}$

$:\implies\sf{3(\dfrac{20}{9}-\dfrac{1}{1})=5-(\dfrac{10}{3}-\dfrac{2}{1})}$

$:\implies\sf{3(\dfrac{20-9}{9})=5-(\dfrac{10-6}{3})}$

$:\implies\sf{\cancel{3}\times\dfrac{11}{\cancel{9}}=\dfrac{5}{1}-\dfrac{4}{3}}$

$:\implies\sf{\dfrac{11}{3}=\dfrac{15-4}{3}}$

$:\implies\sf{\dfrac{11}{3}=\dfrac{11}{3}}$

Hence , the answer is verified.