Question

solve the following equation quratic formula x^2-5x=0​

Answer 1

Step-by-step explanation:

x2−5x=0x2-5x=0

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)2a-b±b2-4(ac)2a

Substitute the values a=1a=1, b=−5b=-5, and c=0c=0 into the quadratic formula and solve for xx.

5±√(−5)2−4⋅(1⋅0)2⋅15±(-5)2-4⋅(1⋅0)2⋅1

Simplify.

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x=5±52x=5±52

The final answer is the combination of both solutions.

x=5,0x=5,0

Answer 2

Step-by-step explanation:

x²-5x=0

x²-5x-0

a=1, b=-5, c=0

BY USING QUADRATIC FORMULA

x= -b√(b)² -4ac /2a

x = -(-5)±√(-5)²-4(1)(0) /2×1

x = 5± √25-0 /2

x = 5±5/2

x = 5+5/2 , 5-5/2

x = 10/2 , 0/2

x = 5. ,. 0

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