Question

solve the following equation quratic formula y^2-14y-12=0​

Answer 1

Answer:

$y = 7 + \sqrt{61} \: \: and \: \: 7 - \sqrt{61}$

Step-by-step explanation:

y² - 14y - 12 =0

a = 1

b = -14

c = -12

D = b² - 4ac

= -14² - 4(1)(-12)

= 196 - (-48)

= 244 > 0

Therefore, the equation has real and distinct roots.

$y = \frac{ - b + \sqrt{b^{2} - 4ac} }{2a} . \frac{ - b - \sqrt{b^{2} - 4ac} }{2a}$

$y = \frac{ 14 + \ \sqrt{244} }{2}. \frac{ 14 - \ \sqrt{244} }{2}$

$y = \frac{ 14 + 2\sqrt{61} }{2}. \frac{ 14 - 2\sqrt{61} }{2}$

$y = 7 + \sqrt{61} \: \: and \: \: 7 - \sqrt{61}$

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